IP=83 . 247 . 59 . 192 / 12


Mask =

Find the Answers for each

  1. What is the Dotted Decimal Subnet Mask?
  2. Find this SubNetwork
  3. Find the First useable IP address
  4. Find the Broadcast address
  5. Find the Last useable IP address
  6. What is the Total Number of IPs per Subnet?
  7. How many useable Hosts Addresses per subnet?
  8. What is the Next Subnetwork Number?
  9. What IP Class is this?
  10. How many possible Subnetworks with this IP Class and mask?

When completed Scroll down for the Answers

Sat, 20 Jan 2018 00:11:16 -0700
© by David Clauss Oct 2012















Repeat
Given IP83 . 247 . 59 . 192 / 12
#1. & 2.Find the SubNetwork
  1. Binary IP= 01010011 . 11110111 . 00111011 . 11000000 .
  2. With a 12 bit mask
  3. Dotted Decimal Subnet Mask = 255 . 240 . 0 . 0
  4. Binary Subnet Mask = 11111111 . 11110000 . 00000000 . 00000000

    Subnetwork Address = 83 . 240 . 0 . 0

#3.Find the First useable IP address 83 . 240 . 0 . 1
#4.Find the Broadcast address83 . 255 . 255 . 255
#5Find the Last useable IP address83 . 255 . 255 . 254
#6.What is the Total Number of IPs per Subnet?1048576
#7.How many useable Hosts address per subnet?1048574
#8.What is the Next Subnet Number?84 . 0 . 0 . 0
#9.What IP Class is this?

Class A

#10.How many possible Subnetworks with this class?
Bits this Class = 8
Bits Subnet Mask= 12

2^ 4 = 16

Also try: Networks Practice

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Sat, 20 Jan 2018 00:11:16 -0700