IP=141 . 60 . 252 . 219 / 27

1. What is the Dotted Decimal Subnet Mask?
2. Find this SubNetwork
3. Find the First useable IP address
5. Find the Last useable IP address
6. What is the Total Number of IPs per Subnet?
7. How many useable Hosts Addresses per subnet?
8. What is the Next Subnetwork Number?
9. What IP Class is this?
10. How many possible Subnetworks with this IP Class and mask?

When completed Scroll down for the Answers Thu, 20 Jun 2019 04:31:29 -0700
© by David Clauss Oct 2012

Repeat
Given IP141 . 60 . 252 . 219 / 27
#1. & 2.Find the SubNetwork
1. Binary IP= 10001101 . 00111100 . 11111100 . 11011011 .
2. With a 27 bit mask
3. Dotted Decimal Subnet Mask = 255 . 255 . 255 . 224
4. Binary Subnet Mask = 11111111 . 11111111 . 11111111 . 11100000

Subnetwork Address = 141 . 60 . 252 . 192

#3.Find the First useable IP address 141 . 60 . 252 . 193
#5Find the Last useable IP address141 . 60 . 252 . 222
#6.What is the Total Number of IPs per Subnet?32
#7.How many useable Hosts address per subnet?30
#8.What is the Next Subnet Number?141 . 60 . 252 . 224
#9.What IP Class is this?

Class B

#10.How many possible Subnetworks with this class?
Bits this Class = 16