IP=198 . 113 . 216 . 97 / 28


Mask =

Find the Answers for each

  1. What is the Dotted Decimal Subnet Mask?
  2. Find this SubNetwork
  3. Find the First useable IP address
  4. Find the Broadcast address
  5. Find the Last useable IP address
  6. What is the Total Number of IPs per Subnet?
  7. How many useable Hosts Addresses per subnet?
  8. What is the Next Subnetwork Number?
  9. What IP Class is this?
  10. How many possible Subnetworks with this IP Class and mask?
  11. What is the 2nd SubNetwork Number?

When completed Scroll down for the Answers

Mon, 21 May 2018 16:57:02 -0700
© by David Clauss Oct 2012















Repeat
Given IP198 . 113 . 216 . 97 / 28
#1. & 2.Find the SubNetwork
  1. Binary IP= 11000110 . 01110001 . 11011000 . 01100001 .
  2. With a 28 bit mask
  3. Dotted Decimal Subnet Mask = 255 . 255 . 255 . 240
  4. Binary Subnet Mask = 11111111 . 11111111 . 11111111 . 11110000

    Subnetwork Address = 198 . 113 . 216 . 96

#3.Find the First useable IP address 198 . 113 . 216 . 97
#4.Find the Broadcast address198 . 113 . 216 . 111
#5Find the Last useable IP address198 . 113 . 216 . 110
#6.What is the Total Number of IPs per Subnet?16
#7.How many useable Hosts address per subnet?14
#8.What is the Next Subnet Number?198 . 113 . 216 . 112
#9.What IP Class is this?

Class C

#10.How many possible Subnetworks with this class?
Bits this Class = 24
Bits Subnet Mask= 28

2^ 4 = 16

#11.What is the 2nd SubNetwork Number?198.113.216.32

Also try: Networks Practice

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Mon, 21 May 2018 16:57:02 -0700