IP=23 . 143 . 249 . 181 / 16


Mask =

Find the Answers for each

  1. What is the Dotted Decimal Subnet Mask?
  2. Find this SubNetwork
  3. Find the First useable IP address
  4. Find the Broadcast address
  5. Find the Last useable IP address
  6. What is the Total Number of IPs per Subnet?
  7. How many useable Hosts Addresses per subnet?
  8. What is the Next Subnetwork Number?
  9. What IP Class is this?
  10. How many possible Subnetworks with this IP Class and mask?

When completed Scroll down for the Answers

Tue, 16 Oct 2018 01:21:59 -0700
© by David Clauss Oct 2012















Repeat
Given IP23 . 143 . 249 . 181 / 16
#1. & 2.Find the SubNetwork
  1. Binary IP= 00010111 . 10001111 . 11111001 . 10110101 .
  2. With a 16 bit mask
  3. Dotted Decimal Subnet Mask = 255 . 255 . 0 . 0
  4. Binary Subnet Mask = 11111111 . 11111111 . 00000000 . 00000000

    Subnetwork Address = 23 . 143 . 0 . 0

#3.Find the First useable IP address 23 . 143 . 0 . 1
#4.Find the Broadcast address23 . 143 . 255 . 255
#5Find the Last useable IP address23 . 143 . 255 . 254
#6.What is the Total Number of IPs per Subnet?65536
#7.How many useable Hosts address per subnet?65534
#8.What is the Next Subnet Number?23 . 144 . 0 . 0
#9.What IP Class is this?

Class A

#10.How many possible Subnetworks with this class?
Bits this Class = 8
Bits Subnet Mask= 16

2^ 8 = 256

Also try: Networks Practice

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Tue, 16 Oct 2018 01:21:59 -0700